ajaxpost带参数请求后台怎么接收参数？

发布时间：2020-04-15 16:50:20

把要发送的json作为字符串传入body即可

public static String sendHttpPost(String url, String body) throws Exception {
CloseableHttpClient httpClient = HttpClients.createDefault();
HttpPost httpPost = new HttpPost(url);
httpPost.addHeader("Content-Type